Calculate no. of choice situations (labeled, full factorial)

[greenvanilla]

Dear all,

I am reading the Ngene handbook and have a problem understanding the calculation on page 95, referring to Table 7.1.
It is said that "the full factorial design has 2^1 x 3^8 x 4^2 = 209,952 choice situations".
I don't understand how exactly this is calculated, particularly the 3^8 part.
I thought that you would multiply the number of levels, but I really don't get where there are 8 times 3 levels.
Can anybody help me?

Thanks a lot in advance!

[Michiel Bliemer]

Yes you can simply multiply the levels, so in that example that would be (looking at Table 7.1):
3*3*4*3*3*4*3*2*3 = 2^1 * 3^6 * 4^2 = 23,328.

So it seems that the calculation in the manual is wrong, it should be 3^6 instead of 3^8. We will correct this in the manual.

Michiel

[greenvanilla]

Thank you very much for your helpful reply, Prof. Bliemer!