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Thank you very much for the quick and very useful answer Michiel!

You helped me a lot!

Have a nice day!

Peter

Hi Michiel!

I have a (maybe too general) question about starting a study.

An orthogonal or an efficient (without any priors) design is the best way to conduct a pilot study?

Have any advantages of efficient design without any prior parameters or worth to use an orthogonal design in the first ...

It worked perfectly!

Thank you very much for your help!

Hi Michiel,

Sorry for the many questions!

In the meantime, I have successfully completed a pilot study using the recommended design:

design
;alts = Service_A*, Service_B*, Service_C*, Service_D*
;rows = 8
;block = 2
;eff = (mnl,d)
;alg = mfederov
;model:
U(Service_A) = b2[0.0001] * int[0,1 ...

Became clear!

Thank you very much!

Dear Michiel!

I would have another question about the Modified Federov algorithm.

How can we determine the values of constraints in case of Modified Federov algorithm.

Is it based on the number of alternatives in decision situations, and the number of attribute levels?

You suggested above that ...

Thank you very much!

It became absolutely clear.

Best regards,
Peter

Maybe a silly question and probably I asked strangely.

I try to creat a maybe better understandable example below.

If I want to analyse three different type of labels (label of origin, fairtrade label, bio label).

What is the main difference between the following ways:

1. I separately use this ...

Dear Michiel!

Thank you very much for your help!

It worked!

In meantime, another question arised in me. Another approach.

In this case, I have only 2 attributes (with 3-5 levels).

What is the difference if I handle the two-level attributes as the following:

design
;alts = Service_A, Service_B ...

Hi Michiel,

I have tried to run two design in Ngene and I have some problem.

For design 1:

I have 4 attributes with 2-2-2-5 levels (in unlabelled case).

My design is the following:

design
;alts = Service_A, Service_B, Service_C, Service_D
;rows = 8
;block = 2
;eff = (mnl,d)
;model:
U(Service_A ...