choice-metrics.com

Michiel

"Releasing new versions is simply a matter of time and cost. We chose for a business model in which users only have to pay once and we have been giving software updates for free for the past 7 years. If we would have chosen for a business model with annual fees, which would generate much ...

Hi all

I'm used to conduct DoE for several alternatives but I need to run
- an orthogonal design in order to define situations to test a product
Factors :
type[1,2,3,4]
moment[1,2,3]
position[1,2,3]
rame[1,2,3]
control[1,2,3]$
-I could have a constraint I may can't go over 32 tests..

That ...

Hi All


A small silly question, how can I add constraints on continuous attribute.. I would like to fix threshold base on other attributes levels
Design

;alts = alt1*,alt2*,alt3*,alt4*,alt5*,none
;rows = 400
;block= 50
;eff = (mnl,d)
;cond:
if(alt1.booking1=4, alt1.seat1=1),
if(alt3.booking3=4 ...

thanks a lot

I came out with the following syntax that works quite fine.

I would like that every respondent faces situations from both design
The ficher rejected that models show different number of alternatives...

Design
;alts(m3) = alt1,alt2,alt3,alt4,alt5,alt6,none
;alts(m2) = alt1,alt2,alt3 ...

Bliemer


I made a confusion between alternatives and choices.
I want to build a choice situation with 4 alternatives that can be structured into 2 pairs (alt1&2, 3&4)
The attributes are brand, price, comfort, and additional price for comfort
Alt1 & Alt3 has no comfort option, 2 & 4 are same ...

tried to reply several times.. nothing appeared, sorry for the multiple posting

Thanks Bliemier

1- Sorry, I forgot I can specify different models within one DoE... It is described in the manual page 130-33..

2- For the second question, one will choose the Train / departure time (day/night) but then he can choose 1st, 2nd class .. How can I build such DoE
To be more precise ...

Hello,

Two questions for one case. Let's take the transport example
Design
;alts(model1) = car, bus, train
;rows = 12
;eff = model1(d)
;alg = swap(reset=10000, resetinc=5000)
;model(model1):
U(car) = /
U(bus) = /
U(train) =
1- Is it possible to request for different number of alternatives?
for ...